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Sin(x) has a maximum value of +1 and a minimum value of -1.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
what is the value of sin 75 degree
1
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
0.96593 (rounded)
2 sin(x) - 3 = 0 2 sin(x) = 3 sin(x) = 1.5 No solution. The maximum value of the sine function is 1.0 .
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
As θ increases from 0 to π/2 (90o) sin θ increases until it reaches a maximum value of 1 when θ = π/2. As θ increases from π/2 (90o) to 3π/2 (270o) sin θ decreases until it reaches a minimum value of -1 when θ = 3π/2. As θ increases from 3π/2 (270o) to 3π (360o) sin θ increases until it reaches the value of 0 it had when θ = 0. From this point, as θ increases (by the same amounts) sin θ repeats this same cyclic behaviour.
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
sin(theta) reach a maximum at pi / 2 + all even multiple of 2 pi. As a result, the smallest positive value of x where y = sin(2x) is maximal is pi / 2.